Click here to get an answer to your question ✍️ in figure, ps is the bisector of \( \angle q p r \) and \( p t \perp q r \). - Ps Is The Bisector Of Angle Qpr

Ps Is The Bisector Of Angle Qpr. Prove that / = / given : Pqr and ps is the bisector of qpr i.e. ∵ ps is the bisector of ∠qpr ∴ ∠qps = ∠rps⇒ ∠1 + ∠tps = ∠2.(1)in ∆pqt,∠ptq = 90°

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Ps is the bisector of ∠p. Draw re parallel ps to meet qp . In δpqr, ps is the bisector of ∠qpr pr = 42 cm, qr = 24 cm and qs is 4 cm less than sr.

Click here to get an answer to your question ✍️ in figure, ps is the bisector of \( \angle q p r \) and \( p t \perp q r \).

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Thales theorem and angle bisector theorem.

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Therefore, pt=pr sides opposite to equal angles of a trinagle are equal.

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